2^6-x=4^2+x

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Solution for 2^6-x=4^2+x equation: 



2^6-x=4^2+x

We move all terms to the left:

2^6-x-(4^2+x)=0

We add all the numbers together, and all the variables

-1x-(4^2+x)+64=0

We get rid of parentheses

-1x-x+64-4^2=0

We add all the numbers together, and all the variables

-2x+48=0

We move all terms containing x to the left, all other terms to the right

-2x=-48

x=-48/-2

x=+24

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